What are the solutions to the equation 40x+2x^2-2x^3=0 ?

The solutions to the equation 40x+2x^2-2x^3=0 are x=0,x=-4,x=5

Find the zeros of 40x+2x^2-2x^3=0

The zeros of 40x+2x^2-2x^3=0 are x=0,x=-4,x=5

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40 x + 2 x^{2} - 2 x^{3} = 0

x = 0, x = - 4, x = 5

Solution steps

40 x + 2 x^{2} - 2 x^{3} = 0

Factor

40 x + 2 x^{2} - 2 x^{3} : - 2 x (x + 4) (x - 5)

- 2 x (x + 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0 or x - 5 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 5 = 0 : x = 5

The solutions are

x = 0, x = - 4, x = 5

- x (x^{2} - 1) (x^{2} + 4) = 0

x^{5} - 3 x + 1 = 0

- 2 (9 x^{2} - 49) (x^{2} - 5) = 0

x^{4} - 7 x^{3} + 12 x^{2} + 4 x - 16 = 0

x^{4} - 38 x^{2} + 72 = 0

What are the solutions to the equation 40x+2x^2-2x^3=0 ?
The solutions to the equation 40x+2x^2-2x^3=0 are x=0,x=-4,x=5
Find the zeros of 40x+2x^2-2x^3=0
The zeros of 40x+2x^2-2x^3=0 are x=0,x=-4,x=5