What are the solutions to the equation x(x^2-9)=4(9-x^2) ?

The solutions to the equation x(x^2-9)=4(9-x^2) are x=-3,x=3,x=-4

Find the zeros of x(x^2-9)=4(9-x^2)

The zeros of x(x^2-9)=4(9-x^2) are x=-3,x=3,x=-4

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x (x^{2} - 9) = 4 (9 - x^{2})

x = - 3, x = 3, x = - 4

Solution steps

x (x^{2} - 9) = 4 (9 - x^{2})

Move

4 (9 - x^{2})

to the left side

x (x^{2} - 9) - 4 (9 - x^{2}) = 0

Factor

x (x^{2} - 9) - 4 (9 - x^{2}) : (x + 3) (x - 3) (x + 4)

(x + 3) (x - 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0 or x + 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

The solutions are

x = - 3, x = 3, x = - 4

x^{4} - x^{3} + 3 x^{2} - 9 x - 54 = 0

x^{3} + 3 x^{2} + 4 x + 2 = 0

2 x^{3} + 5 x^{2} + 32 x + 80 = 0

0 = x^{4}

t^{4} - 81 = 0

What are the solutions to the equation x(x^2-9)=4(9-x^2) ?
The solutions to the equation x(x^2-9)=4(9-x^2) are x=-3,x=3,x=-4
Find the zeros of x(x^2-9)=4(9-x^2)
The zeros of x(x^2-9)=4(9-x^2) are x=-3,x=3,x=-4