What are the solutions to the equation 2x^3+5x^2+32x+80=0 ?

The solutions to the equation 2x^3+5x^2+32x+80=0 are x=-5/2 ,x=4i,x=-4i

Find the zeros of 2x^3+5x^2+32x+80=0

The zeros of 2x^3+5x^2+32x+80=0 are x=-5/2 ,x=4i,x=-4i

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2 x^{3} + 5 x^{2} + 32 x + 80 = 0

x = - \frac{5}{2}, x = 4 i, x = - 4 i

Solution steps

2 x^{3} + 5 x^{2} + 32 x + 80 = 0

Factor

2 x^{3} + 5 x^{2} + 32 x + 80 : (2 x + 5) (x^{2} + 16)

(2 x + 5) (x^{2} + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 5 = 0 or x^{2} + 16 = 0

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

x^{2} + 16 = 0 : x = 4 i, x = - 4 i

The solutions are

x = - \frac{5}{2}, x = 4 i, x = - 4 i

0 = x^{4}

t^{4} - 81 = 0

y^{4} = y^{2}

(1 + \frac{x}{4})^{4} = 22.5

4 x^{5} - x^{3} + 32 x^{2} - 8 = 0

What are the solutions to the equation 2x^3+5x^2+32x+80=0 ?
The solutions to the equation 2x^3+5x^2+32x+80=0 are x=-5/2 ,x=4i,x=-4i
Find the zeros of 2x^3+5x^2+32x+80=0
The zeros of 2x^3+5x^2+32x+80=0 are x=-5/2 ,x=4i,x=-4i