What are the solutions to the equation (1+x/4)^4=22.5 ?

The solutions to the equation (1+x/4)^4=22.5 are x=4.71175…,x=-12.71175…

Find the zeros of (1+x/4)^4=22.5

The zeros of (1+x/4)^4=22.5 are x=4.71175…,x=-12.71175…

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(1 + \frac{x}{4})^{4} = 22.5

x = 4.71175 \dots, x = - 12.71175 \dots

Solution steps

(1 + \frac{x}{4})^{4} = 22.5

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 4.71175 \dots, x = - 12.71175 \dots

4 x^{5} - x^{3} + 32 x^{2} - 8 = 0

- 2 x^{5} + 32 x^{3} = 0

(x + 1)^{3} = 8

(z^{2} + 5)^{3} = 0

- 3 x^{3} - 7 x^{2} - 12 x - 28 = 0

What are the solutions to the equation (1+x/4)^4=22.5 ?
The solutions to the equation (1+x/4)^4=22.5 are x=4.71175…,x=-12.71175…
Find the zeros of (1+x/4)^4=22.5
The zeros of (1+x/4)^4=22.5 are x=4.71175…,x=-12.71175…