What are the solutions to the equation -3x^3-7x^2-12x-28=0 ?

The solutions to the equation -3x^3-7x^2-12x-28=0 are x=-7/3 ,x=2i,x=-2i

Find the zeros of -3x^3-7x^2-12x-28=0

The zeros of -3x^3-7x^2-12x-28=0 are x=-7/3 ,x=2i,x=-2i

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- 3 x^{3} - 7 x^{2} - 12 x - 28 = 0

x = - \frac{7}{3}, x = 2 i, x = - 2 i

Solution steps

- 3 x^{3} - 7 x^{2} - 12 x - 28 = 0

Factor

- 3 x^{3} - 7 x^{2} - 12 x - 28 : - (3 x + 7) (x^{2} + 4)

- (3 x + 7) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 7 = 0 or x^{2} + 4 = 0

Solve

3 x + 7 = 0 : x = - \frac{7}{3}

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - \frac{7}{3}, x = 2 i, x = - 2 i

4 x^{3} + 8 x^{2} + x = 3

- 2 x^{3} + 2 x^{2} - 8 x + 7 = 0

2 x^{3} + 3 x^{2} - 8 x - 3 = 0

x, 9 y = x^{3}

3 (x^{2} - 81) (64 x^{2} - 25) = 0

What are the solutions to the equation -3x^3-7x^2-12x-28=0 ?
The solutions to the equation -3x^3-7x^2-12x-28=0 are x=-7/3 ,x=2i,x=-2i
Find the zeros of -3x^3-7x^2-12x-28=0
The zeros of -3x^3-7x^2-12x-28=0 are x=-7/3 ,x=2i,x=-2i