What are the solutions to the equation 4x^3+8x^2+x=3 ?

The solutions to the equation 4x^3+8x^2+x=3 are x=-1,x= 1/2 ,x=-3/2

Find the zeros of 4x^3+8x^2+x=3

The zeros of 4x^3+8x^2+x=3 are x=-1,x= 1/2 ,x=-3/2

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4 x^{3} + 8 x^{2} + x = 3

x = - 1, x = \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = - 1, x = 0.5, x = - 1.5

Solution steps

4 x^{3} + 8 x^{2} + x = 3

Move

3

to the left side

4 x^{3} + 8 x^{2} + x - 3 = 0

Factor

4 x^{3} + 8 x^{2} + x - 3 : (x + 1) (2 x - 1) (2 x + 3)

(x + 1) (2 x - 1) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x - 1 = 0 or 2 x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions are

x = - 1, x = \frac{1}{2}, x = - \frac{3}{2}

- 2 x^{3} + 2 x^{2} - 8 x + 7 = 0

2 x^{3} + 3 x^{2} - 8 x - 3 = 0

x, 9 y = x^{3}

3 (x^{2} - 81) (64 x^{2} - 25) = 0

- x (x + 9) (x^{2} - 9) = 0

What are the solutions to the equation 4x^3+8x^2+x=3 ?
The solutions to the equation 4x^3+8x^2+x=3 are x=-1,x= 1/2 ,x=-3/2
Find the zeros of 4x^3+8x^2+x=3
The zeros of 4x^3+8x^2+x=3 are x=-1,x= 1/2 ,x=-3/2