What are the solutions to the equation -x(x+9)(x^2-9)=0 ?

The solutions to the equation -x(x+9)(x^2-9)=0 are x=0,x=-9,x=-3,x=3

Find the zeros of -x(x+9)(x^2-9)=0

The zeros of -x(x+9)(x^2-9)=0 are x=0,x=-9,x=-3,x=3

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- x (x + 9) (x^{2} - 9) = 0

x = 0, x = - 9, x = - 3, x = 3

Solution steps

- x (x + 9) (x^{2} - 9) = 0

Factor

- x (x + 9) (x^{2} - 9) : - x (x + 9) (x + 3) (x - 3)

- x (x + 9) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 9 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 9 = 0 : x = - 9

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 9, x = - 3, x = 3

27 x^{3} + 27 x^{2} + 9 x + 1 = 0

4 x^{17} = 68

- x^{3} + x^{2} + 6 x = 0

(81 x^{2} - 100) (x^{2} - 14) = 0

6 x + 21 x^{2} + 12 x^{3} = 0

What are the solutions to the equation -x(x+9)(x^2-9)=0 ?
The solutions to the equation -x(x+9)(x^2-9)=0 are x=0,x=-9,x=-3,x=3
Find the zeros of -x(x+9)(x^2-9)=0
The zeros of -x(x+9)(x^2-9)=0 are x=0,x=-9,x=-3,x=3