What are the solutions to the equation -x^3+x^2+6x=0 ?

The solutions to the equation -x^3+x^2+6x=0 are x=0,x=-2,x=3

Find the zeros of -x^3+x^2+6x=0

The zeros of -x^3+x^2+6x=0 are x=0,x=-2,x=3

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- x^{3} + x^{2} + 6 x = 0

x = 0, x = - 2, x = 3

Solution steps

- x^{3} + x^{2} + 6 x = 0

Factor

- x^{3} + x^{2} + 6 x : - x (x + 2) (x - 3)

- x (x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 2, x = 3

(81 x^{2} - 100) (x^{2} - 14) = 0

6 x + 21 x^{2} + 12 x^{3} = 0

2 x^{5} - 4 x - 7 = 0

2 x^{3} - x^{2} + 11 x - 5 = 0

12 (k (k^{2} - 4 k + 1) + 6) = 0

What are the solutions to the equation -x^3+x^2+6x=0 ?
The solutions to the equation -x^3+x^2+6x=0 are x=0,x=-2,x=3
Find the zeros of -x^3+x^2+6x=0
The zeros of -x^3+x^2+6x=0 are x=0,x=-2,x=3