What are the solutions to the equation 4x^3+3x^2+100x+75=0 ?

The solutions to the equation 4x^3+3x^2+100x+75=0 are x=-3/4 ,x=5i,x=-5i

Find the zeros of 4x^3+3x^2+100x+75=0

The zeros of 4x^3+3x^2+100x+75=0 are x=-3/4 ,x=5i,x=-5i

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4 x^{3} + 3 x^{2} + 100 x + 75 = 0

x = - \frac{3}{4}, x = 5 i, x = - 5 i

Solution steps

4 x^{3} + 3 x^{2} + 100 x + 75 = 0

Factor

4 x^{3} + 3 x^{2} + 100 x + 75 : (4 x + 3) (x^{2} + 25)

(4 x + 3) (x^{2} + 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 3 = 0 or x^{2} + 25 = 0

Solve

4 x + 3 = 0 : x = - \frac{3}{4}

Solve

x^{2} + 25 = 0 : x = 5 i, x = - 5 i

The solutions are

x = - \frac{3}{4}, x = 5 i, x = - 5 i

4 x^{3} = x

x, 2 y^{2} = x^{3}

x^{3} + 4 x^{2} - 11 x - 30 = 0

z^{4} = 3

z^{4} = 2

What are the solutions to the equation 4x^3+3x^2+100x+75=0 ?
The solutions to the equation 4x^3+3x^2+100x+75=0 are x=-3/4 ,x=5i,x=-5i
Find the zeros of 4x^3+3x^2+100x+75=0
The zeros of 4x^3+3x^2+100x+75=0 are x=-3/4 ,x=5i,x=-5i