What are the solutions to the equation 7x^4=1512x ?

The solutions to the equation 7x^4=1512x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

Find the zeros of 7x^4=1512x

The zeros of 7x^4=1512x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

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7 x^{4} = 1512 x

x = 0, x = 6, x = - 3 + 33 i, x = - 3 - 33 i

Solution steps

7 x^{4} = 1512 x

Move

1512 x

to the left side

7 x^{4} - 1512 x = 0

Factor

7 x^{4} - 1512 x : 7 x (x - 6) (x^{2} + 6 x + 36)

7 x (x - 6) (x^{2} + 6 x + 36) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 6 = 0 or x^{2} + 6 x + 36 = 0

Solve

x - 6 = 0 : x = 6

Solve

x^{2} + 6 x + 36 = 0 : x = - 3 + 33 i, x = - 3 - 33 i

The solutions are

x = 0, x = 6, x = - 3 + 33 i, x = - 3 - 33 i

(x - 3) (x^{2} - 4 x + 4) = 0

x^{3} + 5 x - 7 = 0

x^{3} - 6 x^{2} + 8 x = x^{2} - 4 x

2 t^{3} + t^{2} - 10 t = 0

x^{2} (x + 1) + 4 (x + 1) = 0

What are the solutions to the equation 7x^4=1512x ?
The solutions to the equation 7x^4=1512x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i
Find the zeros of 7x^4=1512x
The zeros of 7x^4=1512x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i