What are the solutions to the equation (2m^2+7m+4)m=0 ?

The solutions to the equation (2m^2+7m+4)m=0 are m=(-7+sqrt(17))/4 ,m=(-7-sqrt(17))/4 ,m=0

Find the zeros of (2m^2+7m+4)m=0

The zeros of (2m^2+7m+4)m=0 are m=(-7+sqrt(17))/4 ,m=(-7-sqrt(17))/4 ,m=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 m^{2} + 7 m + 4) m = 0

m = \frac{- 7 + 17}{4}, m = \frac{- 7 - 17}{4}, m = 0

Decimal Notation

m = - 0.71922 \dots, m = - 2.78077 \dots, m = 0

Solution steps

(2 m^{2} + 7 m + 4) m = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 m^{2} + 7 m + 4 = 0 or m = 0

Solve

2 m^{2} + 7 m + 4 = 0 : m = \frac{- 7 + 17}{4}, m = \frac{- 7 - 17}{4}

The solutions are

m = \frac{- 7 + 17}{4}, m = \frac{- 7 - 17}{4}, m = 0

216 = x^{3}

(5 - x) (x + 1) - 3 = (2 - 3 x) (x^{2} + 1)

x, x^{3} + 4 x^{2} - 3 x - 2 = 0

x^{3} - 2 x^{2} - 4 = 0

4 x^{3} - 3 x - 1 = 0

What are the solutions to the equation (2m^2+7m+4)m=0 ?
The solutions to the equation (2m^2+7m+4)m=0 are m=(-7+sqrt(17))/4 ,m=(-7-sqrt(17))/4 ,m=0
Find the zeros of (2m^2+7m+4)m=0
The zeros of (2m^2+7m+4)m=0 are m=(-7+sqrt(17))/4 ,m=(-7-sqrt(17))/4 ,m=0