What are the solutions to the equation 3x^3+49=x^2+147x ?

The solutions to the equation 3x^3+49=x^2+147x are x= 1/3 ,x=-7,x=7

Find the zeros of 3x^3+49=x^2+147x

The zeros of 3x^3+49=x^2+147x are x= 1/3 ,x=-7,x=7

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3 x^{3} + 49 = x^{2} + 147 x

x = \frac{1}{3}, x = - 7, x = 7

Decimal Notation

x = 0.33333 \dots, x = - 7, x = 7

Solution steps

3 x^{3} + 49 = x^{2} + 147 x

Move

147 x

to the left side

3 x^{3} + 49 - 147 x = x^{2}

Move

x^{2}

to the left side

3 x^{3} + 49 - 147 x - x^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

3 x^{3} - x^{2} - 147 x + 49 = 0

Factor

3 x^{3} - x^{2} - 147 x + 49 : (3 x - 1) (x + 7) (x - 7)

(3 x - 1) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x + 7 = 0 or x - 7 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = \frac{1}{3}, x = - 7, x = 7

x^{6} = 0

z^{8} - 1 = 0

x^{3} + 7 x^{2} - 36 = 0

a + 8 = 9 x^{3} - 10

120 x + 8 x^{2} - 2 x^{3} = 0

What are the solutions to the equation 3x^3+49=x^2+147x ?
The solutions to the equation 3x^3+49=x^2+147x are x= 1/3 ,x=-7,x=7
Find the zeros of 3x^3+49=x^2+147x
The zeros of 3x^3+49=x^2+147x are x= 1/3 ,x=-7,x=7