What are the solutions to the equation x^3+7x^2-36=0 ?

The solutions to the equation x^3+7x^2-36=0 are x=2,x=-3,x=-6

Find the zeros of x^3+7x^2-36=0

The zeros of x^3+7x^2-36=0 are x=2,x=-3,x=-6

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x^{3} + 7 x^{2} - 36 = 0

x = 2, x = - 3, x = - 6

Solution steps

x^{3} + 7 x^{2} - 36 = 0

Factor

x^{3} + 7 x^{2} - 36 : (x - 2) (x + 3) (x + 6)

(x - 2) (x + 3) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 3 = 0 or x + 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 2, x = - 3, x = - 6

a + 8 = 9 x^{3} - 10

120 x + 8 x^{2} - 2 x^{3} = 0

5 x^{4} - 15 x^{2} = 0

5 x^{4} - 7 x^{3} - 5 x^{2} + 5 x + 1 = 0

- x^{3} + 3 x^{2} - 7 x + 5 = 0

What are the solutions to the equation x^3+7x^2-36=0 ?
The solutions to the equation x^3+7x^2-36=0 are x=2,x=-3,x=-6
Find the zeros of x^3+7x^2-36=0
The zeros of x^3+7x^2-36=0 are x=2,x=-3,x=-6