What are the solutions to the equation 4x^3=0.25^{1/2} ?

The solutions to the equation 4x^3=0.25^{1/2} are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Find the zeros of 4x^3=0.25^{1/2}

The zeros of 4x^3=0.25^{1/2} are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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4 x^{3} = 0.2 5^{\frac{1}{2}}

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

4 x^{3} = 0.2 5^{\frac{1}{2}}

Divide both sides by

4

x^{3} = 0.125

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

x^{4} - 4 x = 0

x, 12 x^{5} = (4 x^{2}) (C)

x^{3} + 8 x^{2} - 29 x + 44 = 0

x^{3} - 3 x^{2} + 6 = 0

y, y^{4} = x^{3} - 16 x

What are the solutions to the equation 4x^3=0.25^{1/2} ?
The solutions to the equation 4x^3=0.25^{1/2} are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Find the zeros of 4x^3=0.25^{1/2}
The zeros of 4x^3=0.25^{1/2} are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i