What are the solutions to the equation x^2=x(12100x^2-220x+1) ?

The solutions to the equation x^2=x(12100x^2-220x+1) are x=0,x= 1/121 ,x= 1/100

Find the zeros of x^2=x(12100x^2-220x+1)

The zeros of x^2=x(12100x^2-220x+1) are x=0,x= 1/121 ,x= 1/100

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x^{2} = x (12100 x^{2} - 220 x + 1)

x = 0, x = \frac{1}{121}, x = \frac{1}{100}

Decimal Notation

x = 0, x = 0.00826 \dots, x = 0.01

Solution steps

x^{2} = x (12100 x^{2} - 220 x + 1)

Expand

x (12100 x^{2} - 220 x + 1) : 12100 x^{3} - 220 x^{2} + x

x^{2} = 12100 x^{3} - 220 x^{2} + x

Switch sides

12100 x^{3} - 220 x^{2} + x = x^{2}

Move

x^{2}

to the left side

12100 x^{3} - 221 x^{2} + x = 0

Factor

12100 x^{3} - 221 x^{2} + x : x (121 x - 1) (100 x - 1)

x (121 x - 1) (100 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 121 x - 1 = 0 or 100 x - 1 = 0

Solve

121 x - 1 = 0 : x = \frac{1}{121}

Solve

100 x - 1 = 0 : x = \frac{1}{100}

The solutions are

x = 0, x = \frac{1}{121}, x = \frac{1}{100}

x^{3} + 10 x - 5 = 0

0 = x^{3} - 10 x^{2} + 24 x

\frac{125}{64} = 125 r^{6}

x^{6} + 3 x^{3} - 7 = 0

x^{4} - 12 x^{2} = 0

What are the solutions to the equation x^2=x(12100x^2-220x+1) ?
The solutions to the equation x^2=x(12100x^2-220x+1) are x=0,x= 1/121 ,x= 1/100
Find the zeros of x^2=x(12100x^2-220x+1)
The zeros of x^2=x(12100x^2-220x+1) are x=0,x= 1/121 ,x= 1/100