What are the solutions to the equation -x^3+x^2+6x+4=0 ?

The solutions to the equation -x^3+x^2+6x+4=0 are x=-1,x=1+sqrt(5),x=1-sqrt(5)

Find the zeros of -x^3+x^2+6x+4=0

The zeros of -x^3+x^2+6x+4=0 are x=-1,x=1+sqrt(5),x=1-sqrt(5)

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- x^{3} + x^{2} + 6 x + 4 = 0

x = - 1, x = 1 + 5, x = 1 - 5

Decimal Notation

x = - 1, x = 3.23606 \dots, x = - 1.23606 \dots

Solution steps

- x^{3} + x^{2} + 6 x + 4 = 0

Factor

- x^{3} + x^{2} + 6 x + 4 : - (x + 1) (x^{2} - 2 x - 4)

- (x + 1) (x^{2} - 2 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} - 2 x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} - 2 x - 4 = 0 : x = 1 + 5, x = 1 - 5

The solutions are

x = - 1, x = 1 + 5, x = 1 - 5

2 x^{3} - 5 x^{2} + 50 x - 125 = 0

- 14 x^{3} + 21 x^{2} - 3 = 0

x^{5} = 5 x - 4 x^{3}

2 x (7 x + 1) (9 x^{2} - 25) = 0

6 x^{4} - 14 x^{2} = 0

What are the solutions to the equation -x^3+x^2+6x+4=0 ?
The solutions to the equation -x^3+x^2+6x+4=0 are x=-1,x=1+sqrt(5),x=1-sqrt(5)
Find the zeros of -x^3+x^2+6x+4=0
The zeros of -x^3+x^2+6x+4=0 are x=-1,x=1+sqrt(5),x=1-sqrt(5)