What are the solutions to the equation 0=x^4-3x^3+6x ?

The solutions to the equation 0=x^4-3x^3+6x are x=0,x\approx-1.19582…

Find the zeros of 0=x^4-3x^3+6x

The zeros of 0=x^4-3x^3+6x are x=0,x\approx-1.19582…

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0 = x^{4} - 3 x^{3} + 6 x

x = 0, x \approx - 1.19582 \dots

Solution steps

0 = x^{4} - 3 x^{3} + 6 x

Switch sides

x^{4} - 3 x^{3} + 6 x = 0

Factor

x^{4} - 3 x^{3} + 6 x : x (x^{3} - 3 x^{2} + 6)

x (x^{3} - 3 x^{2} + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{3} - 3 x^{2} + 6 = 0

Solve

x^{3} - 3 x^{2} + 6 = 0 : x \approx - 1.19582 \dots

The solutions are

x = 0, x \approx - 1.19582 \dots

r^{3} - 3 r^{2} + 2 r = 0

b^{3} = 2

8 y^{3} - 8 = 0

- λ^{3} + 12 λ + 16 = 0

k^{3} = 729

What are the solutions to the equation 0=x^4-3x^3+6x ?
The solutions to the equation 0=x^4-3x^3+6x are x=0,x\approx-1.19582…
Find the zeros of 0=x^4-3x^3+6x
The zeros of 0=x^4-3x^3+6x are x=0,x\approx-1.19582…