What are the solutions to the equation y^2(4-y^2)=0 ?

The solutions to the equation y^2(4-y^2)=0 are y=0,y=-2,y=2

Find the zeros of y^2(4-y^2)=0

The zeros of y^2(4-y^2)=0 are y=0,y=-2,y=2

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y^{2} (4 - y^{2}) = 0

y = 0, y = - 2, y = 2

Solution steps

y^{2} (4 - y^{2}) = 0

Factor

y^{2} (4 - y^{2}) : - y^{2} (y + 2) (y - 2)

- y^{2} (y + 2) (y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y + 2 = 0 or y - 2 = 0

Solve

y + 2 = 0 : y = - 2

Solve

y - 2 = 0 : y = 2

The solutions are

y = 0, y = - 2, y = 2

0 = x^{3} + x^{2} - 12 x

5 x^{4} = 0

x^{3} - 11 x^{2} + 24 x = 0

R^{4} + R^{2} - 2 = 0

25 = x^{4}

What are the solutions to the equation y^2(4-y^2)=0 ?
The solutions to the equation y^2(4-y^2)=0 are y=0,y=-2,y=2
Find the zeros of y^2(4-y^2)=0
The zeros of y^2(4-y^2)=0 are y=0,y=-2,y=2