What are the solutions to the equation (x+3)^3-(3-x)^3=0 ?

The solutions to the equation (x+3)^3-(3-x)^3=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i

Find the zeros of (x+3)^3-(3-x)^3=0

The zeros of (x+3)^3-(3-x)^3=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i

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(x + 3)^{3} - (3 - x)^{3} = 0

x = 0, x = 33 i, x = - 33 i

Solution steps

(x + 3)^{3} - (3 - x)^{3} = 0

Factor

(x + 3)^{3} - (3 - x)^{3} : 2 x (x^{2} + 27)

2 x (x^{2} + 27) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 27 = 0

Solve

x^{2} + 27 = 0 : x = 33 i, x = - 33 i

The solutions are

x = 0, x = 33 i, x = - 33 i

x^{3} + 3 x^{2} - 18 x = 0

10 + x + 2 x^{2} = x^{3}

2 = \frac{1}{4} r^{3}

2 x (x + 1) (x^{2} - 36) = 0

x^{3} - 9 x^{2} + 20 x - 12 = 0

What are the solutions to the equation (x+3)^3-(3-x)^3=0 ?
The solutions to the equation (x+3)^3-(3-x)^3=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i
Find the zeros of (x+3)^3-(3-x)^3=0
The zeros of (x+3)^3-(3-x)^3=0 are x=0,x=3sqrt(3)i,x=-3sqrt(3)i