What are the solutions to the equation 2x^3x^2=5 ?

The solutions to the equation 2x^3x^2=5 are x=\sqrt[5]{5/2}

Find the zeros of 2x^3x^2=5

The zeros of 2x^3x^2=5 are x=\sqrt[5]{5/2}

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2 x^{3} x^{2} = 5

Decimal Notation

x = 1.20112 \dots

Solution steps

2 x^{3} x^{2} = 5

Simplify

2 x^{5} = 5

Divide both sides by

2

\frac{2 x ^{5}}{2} = \frac{5}{2}

x^{5} = \frac{5}{2}

For

x^{n} = f (a)

, n is odd, the solution is

z (z + 2) (z - 1) = 0

x + x^{2} + 600 x^{3} = 14500

(\frac{6 a}{7})^{3} = 1728

16 x (x + 1) (x + 2) (x + 3) = 105

x^{3} = \frac{125}{27}

What are the solutions to the equation 2x^3x^2=5 ?
The solutions to the equation 2x^3x^2=5 are x=\sqrt[5]{5/2}
Find the zeros of 2x^3x^2=5
The zeros of 2x^3x^2=5 are x=\sqrt[5]{5/2}