What are the solutions to the equation -x^3-12x^2+60x-64=0 ?

The solutions to the equation -x^3-12x^2+60x-64=0 are x=2,x=-16

Find the zeros of -x^3-12x^2+60x-64=0

The zeros of -x^3-12x^2+60x-64=0 are x=2,x=-16

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- x^{3} - 12 x^{2} + 60 x - 64 = 0

x = 2, x = - 16

Solution steps

- x^{3} - 12 x^{2} + 60 x - 64 = 0

Factor

- x^{3} - 12 x^{2} + 60 x - 64 : - (x - 2)^{2} (x + 16)

- (x - 2)^{2} (x + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 16 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 16 = 0 : x = - 16

The solutions are

x = 2, x = - 16

2 x^{3} + 4 - 6 x = 0

- 12 + 14 (x^{2} - 3) = 2 (x^{2} - 3)^{2}

x^{3} + 6 x^{2} + 9 = 0

x^{3} - 3 x^{2} - 4 x = 0

x^{3} + x - 30 = 0

What are the solutions to the equation -x^3-12x^2+60x-64=0 ?
The solutions to the equation -x^3-12x^2+60x-64=0 are x=2,x=-16
Find the zeros of -x^3-12x^2+60x-64=0
The zeros of -x^3-12x^2+60x-64=0 are x=2,x=-16