What are the solutions to the equation solvefor x,(x)8x^2+4y^2=12 ?

The solutions to the equation solvefor x,(x)8x^2+4y^2=12 are

Find the zeros of solvefor x,(x)8x^2+4y^2=12

The zeros of solvefor x,(x)8x^2+4y^2=12 are

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solve for

x, (x) 8 x^{2} + 4 y^{2} = 12

Solution steps

(x) \cdot 8 x^{2} + 4 y^{2} = 12

Expand

(x) \cdot 8 x^{2} + 4 y^{2} : 8 x^{3} + 4 y^{2}

8 x^{3} + 4 y^{2} = 12

Move

4 y^{2}

to the right side

8 x^{3} = 12 - 4 y^{2}

Divide both sides by

8

x^{3} = \frac{3 - y ^{2}}{2}

For

x^{3} = f (a)

the solutions are

Simplify

x^{5} - 2 x = 0

x^{5} = 1460

x, x^{4} - 10 x^{2} + 9 = 0

x^{4} + 4 x^{3} - 2 x^{2} + 9 = 0

- x^{3} + x + 1 = 0

What are the solutions to the equation solvefor x,(x)8x^2+4y^2=12 ?
The solutions to the equation solvefor x,(x)8x^2+4y^2=12 are
Find the zeros of solvefor x,(x)8x^2+4y^2=12
The zeros of solvefor x,(x)8x^2+4y^2=12 are