What are the solutions to the equation -x^3+x+1=0 ?

The solutions to the equation -x^3+x+1=0 are x\approx 1.32471…

Find the zeros of -x^3+x+1=0

The zeros of -x^3+x+1=0 are x\approx 1.32471…

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- x^{3} + x + 1 = 0

x \approx 1.32471 \dots

Solution steps

- x^{3} + x + 1 = 0

Find one solution for

- x^{3} + x + 1 = 0

using Newton-Raphson:

x \approx 1.32471 \dots

Apply long division:

\frac{- x ^{3} + x + 1}{x - 1.32471 \dots} = - x^{2} - 1.32471 \dots x - 0.75487 \dots

- x^{2} - 1.32471 \dots x - 0.75487 \dots \approx 0

Find one solution for

- x^{2} - 1.32471 \dots x - 0.75487 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 1.32471 \dots

(x + 2) (x + 3) (x + 8) (x + 12) = 4 x^{2}

3 x^{3} + 12 x = 12 x^{2}

3 x^{5} + 15 x = 18 x^{3}

x^{4} + x - 2 = 0

x^{3} + 3 x^{2} + 3 x = 7

What are the solutions to the equation -x^3+x+1=0 ?
The solutions to the equation -x^3+x+1=0 are x\approx 1.32471…
Find the zeros of -x^3+x+1=0
The zeros of -x^3+x+1=0 are x\approx 1.32471…