What are the solutions to the equation 112=4+96t-16t^2 ?

The solutions to the equation 112=4+96t-16t^2 are t= 3/2 ,t= 9/2

Find the zeros of 112=4+96t-16t^2

The zeros of 112=4+96t-16t^2 are t= 3/2 ,t= 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

112 = 4 + 96 t - 16 t^{2}

t = \frac{3}{2}, t = \frac{9}{2}

Decimal Notation

t = 1.5, t = 4.5

Solution steps

112 = 4 + 96 t - 16 t^{2}

Switch sides

4 + 96 t - 16 t^{2} = 112

Move

112

to the left side

- 16 t^{2} + 96 t - 108 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) ( - 108 )}{2 ( - 16 )}

9 6^{2} - 4 (- 16) (- 108) = 48

t_{1, 2} = \frac{- 96 \pm 48}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 48}{2 ( - 16 )}, t_{2} = \frac{- 96 - 48}{2 ( - 16 )}

t = \frac{- 96 + 48}{2 ( - 16 )} : \frac{3}{2}

t = \frac{- 96 - 48}{2 ( - 16 )} : \frac{9}{2}

The solutions to the quadratic equation are:

t = \frac{3}{2}, t = \frac{9}{2}

2 \cdot π \cdot 7

6 z - 7 > 8 z + 2

c^{2} - 10 c + 24

9 x^{2} - 12 x = 0

- 2 \cdot 3^{2}

What are the solutions to the equation 112=4+96t-16t^2 ?
The solutions to the equation 112=4+96t-16t^2 are t= 3/2 ,t= 9/2
Find the zeros of 112=4+96t-16t^2
The zeros of 112=4+96t-16t^2 are t= 3/2 ,t= 9/2