What are the solutions to the equation 9x^2-12x=0 ?

The solutions to the equation 9x^2-12x=0 are x= 4/3 ,x=0

Find the zeros of 9x^2-12x=0

The zeros of 9x^2-12x=0 are x= 4/3 ,x=0

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9 x^{2} - 12 x = 0

x = \frac{4}{3}, x = 0

Decimal Notation

x = 1.33333 \dots, x = 0

Solution steps

9 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 9}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 9}

x = \frac{- ( - 12 ) + 12}{2 \cdot 9} : \frac{4}{3}

x = \frac{- ( - 12 ) - 12}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = 0

- 2 \cdot 3^{2}

x^{2} - 6 x = 17

6 > x - 4

\frac{1}{5} \cdot 75

(52 - e) (32 + e) = f 2 - 6

What are the solutions to the equation 9x^2-12x=0 ?
The solutions to the equation 9x^2-12x=0 are x= 4/3 ,x=0
Find the zeros of 9x^2-12x=0
The zeros of 9x^2-12x=0 are x= 4/3 ,x=0