What are the solutions to the equation 4x^3-4x^2-25x+25=0 ?

The solutions to the equation 4x^3-4x^2-25x+25=0 are x=1,x=-5/2 ,x= 5/2

Find the zeros of 4x^3-4x^2-25x+25=0

The zeros of 4x^3-4x^2-25x+25=0 are x=1,x=-5/2 ,x= 5/2

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4 x^{3} - 4 x^{2} - 25 x + 25 = 0

x = 1, x = - \frac{5}{2}, x = \frac{5}{2}

Decimal Notation

x = 1, x = - 2.5, x = 2.5

Solution steps

4 x^{3} - 4 x^{2} - 25 x + 25 = 0

Factor

4 x^{3} - 4 x^{2} - 25 x + 25 : (x - 1) (2 x + 5) (2 x - 5)

(x - 1) (2 x + 5) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 5 = 0 or 2 x - 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions are

x = 1, x = - \frac{5}{2}, x = \frac{5}{2}

4 x^{3} - 12 x^{2} + 12 x - 4 = 0

36 x^{3} + 24 x^{2} = - 4 x

x^{3} + 2 x^{2} - 6 x + 9 = 0

25 x^{3} - 75 x^{2} - 9 x + 27 = 0

x^{3} - x^{2} = 2 x

What are the solutions to the equation 4x^3-4x^2-25x+25=0 ?
The solutions to the equation 4x^3-4x^2-25x+25=0 are x=1,x=-5/2 ,x= 5/2
Find the zeros of 4x^3-4x^2-25x+25=0
The zeros of 4x^3-4x^2-25x+25=0 are x=1,x=-5/2 ,x= 5/2