What are the solutions to the equation 3x^3-13x^2+13x-3=0 ?

The solutions to the equation 3x^3-13x^2+13x-3=0 are x=1,x= 1/3 ,x=3

Find the zeros of 3x^3-13x^2+13x-3=0

The zeros of 3x^3-13x^2+13x-3=0 are x=1,x= 1/3 ,x=3

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3 x^{3} - 13 x^{2} + 13 x - 3 = 0

x = 1, x = \frac{1}{3}, x = 3

Decimal Notation

x = 1, x = 0.33333 \dots, x = 3

Solution steps

3 x^{3} - 13 x^{2} + 13 x - 3 = 0

Factor

3 x^{3} - 13 x^{2} + 13 x - 3 : (x - 1) (3 x - 1) (x - 3)

(x - 1) (3 x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x - 1 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = \frac{1}{3}, x = 3

y^{3} + 2 y^{2} = 49 y + 98

x^{3} + 10 x^{2} + 25 x + 15 = 0

x^{3} - 3 x + 2 = x + 1

2 x^{3} - 5 x^{2} - 22 x - 15 = 0

2 x^{2} \cdot 4 x^{4} = 512

What are the solutions to the equation 3x^3-13x^2+13x-3=0 ?
The solutions to the equation 3x^3-13x^2+13x-3=0 are x=1,x= 1/3 ,x=3
Find the zeros of 3x^3-13x^2+13x-3=0
The zeros of 3x^3-13x^2+13x-3=0 are x=1,x= 1/3 ,x=3