What are the solutions to the equation y^3+2y^2=49y+98 ?

The solutions to the equation y^3+2y^2=49y+98 are y=-2,y=-7,y=7

Find the zeros of y^3+2y^2=49y+98

The zeros of y^3+2y^2=49y+98 are y=-2,y=-7,y=7

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y^{3} + 2 y^{2} = 49 y + 98

y = - 2, y = - 7, y = 7

Solution steps

y^{3} + 2 y^{2} = 49 y + 98

Move

98

to the left side

y^{3} + 2 y^{2} - 98 = 49 y

Move

49 y

to the left side

y^{3} + 2 y^{2} - 98 - 49 y = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

y^{3} + 2 y^{2} - 49 y - 98 = 0

Factor

y^{3} + 2 y^{2} - 49 y - 98 : (y + 2) (y + 7) (y - 7)

(y + 2) (y + 7) (y - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 2 = 0 or y + 7 = 0 or y - 7 = 0

Solve

y + 2 = 0 : y = - 2

Solve

y + 7 = 0 : y = - 7

Solve

y - 7 = 0 : y = 7

The solutions are

y = - 2, y = - 7, y = 7

x^{3} + 10 x^{2} + 25 x + 15 = 0

x^{3} - 3 x + 2 = x + 1

2 x^{3} - 5 x^{2} - 22 x - 15 = 0

2 x^{2} \cdot 4 x^{4} = 512

x^{3} - 6 x^{2} - 3 x + 18 = 0

What are the solutions to the equation y^3+2y^2=49y+98 ?
The solutions to the equation y^3+2y^2=49y+98 are y=-2,y=-7,y=7
Find the zeros of y^3+2y^2=49y+98
The zeros of y^3+2y^2=49y+98 are y=-2,y=-7,y=7