What are the solutions to the equation x^4+2x^3-24x^2=0 ?

The solutions to the equation x^4+2x^3-24x^2=0 are x=0,x=4,x=-6

Find the zeros of x^4+2x^3-24x^2=0

The zeros of x^4+2x^3-24x^2=0 are x=0,x=4,x=-6

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x^{4} + 2 x^{3} - 24 x^{2} = 0

x = 0, x = 4, x = - 6

Solution steps

x^{4} + 2 x^{3} - 24 x^{2} = 0

Factor

x^{4} + 2 x^{3} - 24 x^{2} : x^{2} (x - 4) (x + 6)

x^{2} (x - 4) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0 or x + 6 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 0, x = 4, x = - 6

27 - x^{3} = 0

400 = \frac{4}{3} π r^{3}

3 x^{4} + x^{2} - 4 = 0

x^{3} = 3 x + 2

2 x (x + 10) (x^{2} + 49) = 0

What are the solutions to the equation x^4+2x^3-24x^2=0 ?
The solutions to the equation x^4+2x^3-24x^2=0 are x=0,x=4,x=-6
Find the zeros of x^4+2x^3-24x^2=0
The zeros of x^4+2x^3-24x^2=0 are x=0,x=4,x=-6