What are the solutions to the equation (30-4x)(20-2x)(x)=0 ?

The solutions to the equation (30-4x)(20-2x)(x)=0 are x= 15/2 ,x=10,x=0

Find the zeros of (30-4x)(20-2x)(x)=0

The zeros of (30-4x)(20-2x)(x)=0 are x= 15/2 ,x=10,x=0

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(30 - 4 x) (20 - 2 x) (x) = 0

x = \frac{15}{2}, x = 10, x = 0

Decimal Notation

x = 7.5, x = 10, x = 0

Solution steps

(30 - 4 x) (20 - 2 x) (x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

30 - 4 x = 0 or 20 - 2 x = 0 or x = 0

Solve

30 - 4 x = 0 : x = \frac{15}{2}

Solve

20 - 2 x = 0 : x = 10

The solutions are

x = \frac{15}{2}, x = 10, x = 0

x^{3} - 30 x^{2} - 1900 x - 18000 = 0

x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4 = 0

x^{4} - 122 x^{2} + 121 = 0

(3 x^{2}) 5 = 3 (2 x^{5})

2 x^{3} - 16 = 0

What are the solutions to the equation (30-4x)(20-2x)(x)=0 ?
The solutions to the equation (30-4x)(20-2x)(x)=0 are x= 15/2 ,x=10,x=0
Find the zeros of (30-4x)(20-2x)(x)=0
The zeros of (30-4x)(20-2x)(x)=0 are x= 15/2 ,x=10,x=0