What are the solutions to the equation 4a^3-a^2=2a^2 ?

The solutions to the equation 4a^3-a^2=2a^2 are a=0,a= 3/4

Find the zeros of 4a^3-a^2=2a^2

The zeros of 4a^3-a^2=2a^2 are a=0,a= 3/4

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4 a^{3} - a^{2} = 2 a^{2}

a = 0, a = \frac{3}{4}

Decimal Notation

a = 0, a = 0.75

Solution steps

4 a^{3} - a^{2} = 2 a^{2}

Move

2 a^{2}

to the left side

4 a^{3} - 3 a^{2} = 0

Factor

4 a^{3} - 3 a^{2} : a^{2} (4 a - 3)

a^{2} (4 a - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0 or 4 a - 3 = 0

Solve

4 a - 3 = 0 : a = \frac{3}{4}

The solutions are

a = 0, a = \frac{3}{4}

x^{4} - 12 x^{3} + 48 x^{2} - 64 x = 0

12 x^{2} - 12 x^{3} = 0

2 x^{3} - 3 x^{2} - 4 x + 6 = 0

z^{6} - 28 z^{3} + 27 = 0

- 5 + n^{3} = - 8

What are the solutions to the equation 4a^3-a^2=2a^2 ?
The solutions to the equation 4a^3-a^2=2a^2 are a=0,a= 3/4
Find the zeros of 4a^3-a^2=2a^2
The zeros of 4a^3-a^2=2a^2 are a=0,a= 3/4