What are the solutions to the equation 2x^3+7x^2-28x-98=0 ?

The solutions to the equation 2x^3+7x^2-28x-98=0 are x=-7/2 ,x=-sqrt(14),x=sqrt(14)

Find the zeros of 2x^3+7x^2-28x-98=0

The zeros of 2x^3+7x^2-28x-98=0 are x=-7/2 ,x=-sqrt(14),x=sqrt(14)

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2 x^{3} + 7 x^{2} - 28 x - 98 = 0

x = - \frac{7}{2}, x = - 14, x = 14

Decimal Notation

x = - 3.5, x = - 3.74165 \dots, x = 3.74165 \dots

Solution steps

2 x^{3} + 7 x^{2} - 28 x - 98 = 0

Factor

2 x^{3} + 7 x^{2} - 28 x - 98 : (2 x + 7) (x + 14) (x - 14)

(2 x + 7) (x + 14) (x - 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 7 = 0 or x + 14 = 0 or x - 14 = 0

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

Solve

x + 14 = 0 : x = - 14

Solve

x - 14 = 0 : x = 14

The solutions are

x = - \frac{7}{2}, x = - 14, x = 14

5 t^{3} - 20 t = 0

2 x^{3} - 19 x^{2} + 8 x + 9 = 0

y^{3} - 49 y = 0

x^{4} + 8 x^{2} - 48 = 0

3 y^{3} - 14 y^{2} - 5 y = 0

What are the solutions to the equation 2x^3+7x^2-28x-98=0 ?
The solutions to the equation 2x^3+7x^2-28x-98=0 are x=-7/2 ,x=-sqrt(14),x=sqrt(14)
Find the zeros of 2x^3+7x^2-28x-98=0
The zeros of 2x^3+7x^2-28x-98=0 are x=-7/2 ,x=-sqrt(14),x=sqrt(14)