What are the solutions to the equation x^3-4x^2+3x+2=0 ?

The solutions to the equation x^3-4x^2+3x+2=0 are x=2,x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of x^3-4x^2+3x+2=0

The zeros of x^3-4x^2+3x+2=0 are x=2,x=1+sqrt(2),x=1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 4 x^{2} + 3 x + 2 = 0

x = 2, x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2, x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

x^{3} - 4 x^{2} + 3 x + 2 = 0

Factor

x^{3} - 4 x^{2} + 3 x + 2 : (x - 2) (x^{2} - 2 x - 1)

(x - 2) (x^{2} - 2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - 2 x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 2 x - 1 = 0 : x = 1 + 2, x = 1 - 2

The solutions are

x = 2, x = 1 + 2, x = 1 - 2

x^{3} + 2 x^{2} - 11 x = 12

(5 x^{2} - 12 x - 9) (4 x + a) = 0

48 x^{3} - 64 x^{2} - 3 x + 4 = 0

(3 x + 2) (x + 9) (x - 2) = 0

15 x^{4} - 75 x^{2} + 60 = 0

What are the solutions to the equation x^3-4x^2+3x+2=0 ?
The solutions to the equation x^3-4x^2+3x+2=0 are x=2,x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of x^3-4x^2+3x+2=0
The zeros of x^3-4x^2+3x+2=0 are x=2,x=1+sqrt(2),x=1-sqrt(2)