What are the solutions to the equation (3x+2)(x+9)(x-2)=0 ?

The solutions to the equation (3x+2)(x+9)(x-2)=0 are x=-2/3 ,x=-9,x=2

Find the zeros of (3x+2)(x+9)(x-2)=0

The zeros of (3x+2)(x+9)(x-2)=0 are x=-2/3 ,x=-9,x=2

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(3 x + 2) (x + 9) (x - 2) = 0

x = - \frac{2}{3}, x = - 9, x = 2

Decimal Notation

x = - 0.66666 \dots, x = - 9, x = 2

Solution steps

(3 x + 2) (x + 9) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or x + 9 = 0 or x - 2 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x + 9 = 0 : x = - 9

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{2}{3}, x = - 9, x = 2

15 x^{4} - 75 x^{2} + 60 = 0

x^{3} - 6 x^{2} + 11 x = 6

(u^{2} - 5 u - 6) (5 u + 25) = 0

x^{6} - 2 x^{4} = 0

10 = 500 x^{3}

What are the solutions to the equation (3x+2)(x+9)(x-2)=0 ?
The solutions to the equation (3x+2)(x+9)(x-2)=0 are x=-2/3 ,x=-9,x=2
Find the zeros of (3x+2)(x+9)(x-2)=0
The zeros of (3x+2)(x+9)(x-2)=0 are x=-2/3 ,x=-9,x=2