What are the solutions to the equation x^3+4x^2-5=0 ?

The solutions to the equation x^3+4x^2-5=0 are x=1,x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2

Find the zeros of x^3+4x^2-5=0

The zeros of x^3+4x^2-5=0 are x=1,x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2

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x^{3} + 4 x^{2} - 5 = 0

x = 1, x = \frac{- 5 + 5}{2}, x = \frac{- 5 - 5}{2}

Decimal Notation

x = 1, x = - 1.38196 \dots, x = - 3.61803 \dots

Solution steps

x^{3} + 4 x^{2} - 5 = 0

Factor

x^{3} + 4 x^{2} - 5 : (x - 1) (x^{2} + 5 x + 5)

(x - 1) (x^{2} + 5 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} + 5 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + 5 x + 5 = 0 : x = \frac{- 5 + 5}{2}, x = \frac{- 5 - 5}{2}

The solutions are

x = 1, x = \frac{- 5 + 5}{2}, x = \frac{- 5 - 5}{2}

- 34 = 3 x^{4} + 118

x^{7} - 7 x^{6} = 0

12 x^{4} - 7 x^{2} - 6 x + 16 x^{3} = 0

19 = 32 (1 - b)^{26}

x^{3} + x = - 2

What are the solutions to the equation x^3+4x^2-5=0 ?
The solutions to the equation x^3+4x^2-5=0 are x=1,x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2
Find the zeros of x^3+4x^2-5=0
The zeros of x^3+4x^2-5=0 are x=1,x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2