What are the solutions to the equation x^5-3x^3-4x^2+2x+4=0 ?

The solutions to the equation x^5-3x^3-4x^2+2x+4=0 are x=-1,x=1,x=2,x=-1+i,x=-1-i

Find the zeros of x^5-3x^3-4x^2+2x+4=0

The zeros of x^5-3x^3-4x^2+2x+4=0 are x=-1,x=1,x=2,x=-1+i,x=-1-i

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x^{5} - 3 x^{3} - 4 x^{2} + 2 x + 4 = 0

x = - 1, x = 1, x = 2, x = - 1 + i, x = - 1 - i

Solution steps

x^{5} - 3 x^{3} - 4 x^{2} + 2 x + 4 = 0

Factor

x^{5} - 3 x^{3} - 4 x^{2} + 2 x + 4 : (x + 1) (x - 1) (x - 2) (x^{2} + 2 x + 2)

(x + 1) (x - 1) (x - 2) (x^{2} + 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x - 2 = 0 or x^{2} + 2 x + 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 2 = 0 : x = - 1 + i, x = - 1 - i

The solutions are

x = - 1, x = 1, x = 2, x = - 1 + i, x = - 1 - i

n^{3} = 60

- x^{3} + 3 x^{2} + 6 x - 8 = 0

x^{3} - 8 x = 0

x^{3} = x + 2

x^{3} - 13 x^{2} + 42 x = 0

What are the solutions to the equation x^5-3x^3-4x^2+2x+4=0 ?
The solutions to the equation x^5-3x^3-4x^2+2x+4=0 are x=-1,x=1,x=2,x=-1+i,x=-1-i
Find the zeros of x^5-3x^3-4x^2+2x+4=0
The zeros of x^5-3x^3-4x^2+2x+4=0 are x=-1,x=1,x=2,x=-1+i,x=-1-i