What are the solutions to the equation (m^2-10m+29)^2=0 ?

The solutions to the equation (m^2-10m+29)^2=0 are m=5+2i,m=5-2i

Find the zeros of (m^2-10m+29)^2=0

The zeros of (m^2-10m+29)^2=0 are m=5+2i,m=5-2i

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(m^{2} - 10 m + 29)^{2} = 0

m = 5 + 2 i, m = 5 - 2 i

Solution steps

(m^{2} - 10 m + 29)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

m^{2} - 10 m + 29 = 0 : m = 5 + 2 i, m = 5 - 2 i

The solutions are

m = 5 + 2 i, m = 5 - 2 i

x^{3} - 4 x^{2} - 25 x + 100 = 0

(2 x - x^{2})^{5} = 0

4 x^{6} - 19 x^{4} + 11 x^{2} + 4 = 0

x (x + 1) (x + 2) = 9240

b^{4} = 16

What are the solutions to the equation (m^2-10m+29)^2=0 ?
The solutions to the equation (m^2-10m+29)^2=0 are m=5+2i,m=5-2i
Find the zeros of (m^2-10m+29)^2=0
The zeros of (m^2-10m+29)^2=0 are m=5+2i,m=5-2i