What are the solutions to the equation z^5+32=0 ?

The solutions to the equation z^5+32=0 are z=-2

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z^5+32=0

z^{5} + 32 = 0

z = - 2

Solution steps

z^{5} + 32 = 0

Move

32

to the right side

z^{5} = - 32

For

x^{n} = f (a)

, n is odd, the solution is

x = n f (a)

z = 5 - 32

5 - 32 = - 2

z = - 2

x^{3} + 6 x^{2} + 4 x + 24 = 0

x^{3} - 2 x^{2} - x + 7 = x^{2} - 3 x + 7

a^{3} - 3 a - 2 = 0

2 x^{3} - 3 x = 0

x^{3} - 20 = 7

What are the solutions to the equation z^5+32=0 ?
The solutions to the equation z^5+32=0 are z=-2
Find the zeros of z^5+32=0
The zeros of z^5+32=0 are z=-2