What are the solutions to the equation 2x^4-9x^3-9x^2+81x-81=0 ?

The solutions to the equation 2x^4-9x^3-9x^2+81x-81=0 are x=-3,x=3,x= 3/2

Find the zeros of 2x^4-9x^3-9x^2+81x-81=0

The zeros of 2x^4-9x^3-9x^2+81x-81=0 are x=-3,x=3,x= 3/2

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2 x^{4} - 9 x^{3} - 9 x^{2} + 81 x - 81 = 0

x = - 3, x = 3, x = \frac{3}{2}

Decimal Notation

x = - 3, x = 3, x = 1.5

Solution steps

2 x^{4} - 9 x^{3} - 9 x^{2} + 81 x - 81 = 0

Factor

2 x^{4} - 9 x^{3} - 9 x^{2} + 81 x - 81 : (x + 3) (x - 3)^{2} (2 x - 3)

(x + 3) (x - 3)^{2} (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0 or 2 x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = - 3, x = 3, x = \frac{3}{2}

x^{3} - 4 x^{2} + x - 4 = x^{2} + 1

4 x^{3} + 24 x^{2} + 36 x = 0

x^{3} - 4 x^{2} - 2 x + 3 = 0

x^{3} - 6 x^{2} + 9 x + 2 = 0

(- x - 2) (x^{2} + 4 x + 3) = 0

What are the solutions to the equation 2x^4-9x^3-9x^2+81x-81=0 ?
The solutions to the equation 2x^4-9x^3-9x^2+81x-81=0 are x=-3,x=3,x= 3/2
Find the zeros of 2x^4-9x^3-9x^2+81x-81=0
The zeros of 2x^4-9x^3-9x^2+81x-81=0 are x=-3,x=3,x= 3/2