What are the solutions to the equation x0.12x^2+40x-32=0 ?

The solutions to the equation x0.12x^2+40x-32=0 are x\approx 0.79847…

Find the zeros of x0.12x^2+40x-32=0

The zeros of x0.12x^2+40x-32=0 are x\approx 0.79847…

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x 0.12 x^{2} + 40 x - 32 = 0

x \approx 0.79847 \dots

Solution steps

x \cdot 0.12 x^{2} + 40 x - 32 = 0

Multiply both sides by

100

12 x^{3} + 4000 x - 3200 = 0

Find one solution for

12 x^{3} + 4000 x - 3200 = 0

using Newton-Raphson:

x \approx 0.79847 \dots

Apply long division:

\frac{12 x ^{3} + 4000 x - 3200}{x - 0.79847 \dots} = 12 x^{2} + 9.58167 \dots x + 4007.65070 \dots

12 x^{2} + 9.58167 \dots x + 4007.65070 \dots \approx 0

Find one solution for

12 x^{2} + 9.58167 \dots x + 4007.65070 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 0.79847 \dots

1.035 = (1 + \frac{r}{4})^{4}

- x^{3} - x + 2 = 0

x^{4} - 3 x^{3} + 3 x^{2} + 1 = 0

2 x^{4} - 12 x^{2} + 16 = 0

- 40 + 6 x^{3} = 0

What are the solutions to the equation x0.12x^2+40x-32=0 ?
The solutions to the equation x0.12x^2+40x-32=0 are x\approx 0.79847…
Find the zeros of x0.12x^2+40x-32=0
The zeros of x0.12x^2+40x-32=0 are x\approx 0.79847…