What are the solutions to the equation 4x^2(x-3)=0 ?

The solutions to the equation 4x^2(x-3)=0 are x=0,x=3

Find the zeros of 4x^2(x-3)=0

The zeros of 4x^2(x-3)=0 are x=0,x=3

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4 x^{2} (x - 3) = 0

x = 0, x = 3

Solution steps

4 x^{2} (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = 3

(4 m^{2} + 2)^{2} = 0

x^{5} + 1024 = 0

x^{3} + 2 x^{2} - 49 x - 98 = 0

(7.2 + x^{2})^{2} = x^{2} + 2.6 7^{2}

6 x^{4} = 1296 x

What are the solutions to the equation 4x^2(x-3)=0 ?
The solutions to the equation 4x^2(x-3)=0 are x=0,x=3
Find the zeros of 4x^2(x-3)=0
The zeros of 4x^2(x-3)=0 are x=0,x=3