What are the solutions to the equation -x^2-6x+16=0 ?

The solutions to the equation -x^2-6x+16=0 are x=-8,x=2

Find the zeros of -x^2-6x+16=0

The zeros of -x^2-6x+16=0 are x=-8,x=2

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- x^{2} - 6 x + 16 = 0

x = - 8, x = 2

Solution steps

- x^{2} - 6 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 16}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 16 = 10

x_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 10}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 10}{2 ( - 1 )} : - 8

x = \frac{- ( - 6 ) - 10}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 8, x = 2

x (4 x + 24) = 0

9^{2} + 1 0^{2} = c^{2}

\frac{14}{5 + 4 x} \leq 7

\frac{r}{10} + 4 = 5

\frac{1}{2} + \frac{1}{3} + \frac{1}{5}

What are the solutions to the equation -x^2-6x+16=0 ?
The solutions to the equation -x^2-6x+16=0 are x=-8,x=2
Find the zeros of -x^2-6x+16=0
The zeros of -x^2-6x+16=0 are x=-8,x=2