What are the solutions to the equation 2y^3-4y^2-3=0 ?

The solutions to the equation 2y^3-4y^2-3=0 are y\approx 2.28682…

Find the zeros of 2y^3-4y^2-3=0

The zeros of 2y^3-4y^2-3=0 are y\approx 2.28682…

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2 y^{3} - 4 y^{2} - 3 = 0

y \approx 2.28682 \dots

Solution steps

2 y^{3} - 4 y^{2} - 3 = 0

Find one solution for

2 y^{3} - 4 y^{2} - 3 = 0

using Newton-Raphson:

y \approx 2.28682 \dots

Apply long division:

\frac{2 y ^{3} - 4 y ^{2} - 3}{y - 2.28682 \dots} = 2 y^{2} + 0.57365 \dots y + 1.31185 \dots

2 y^{2} + 0.57365 \dots y + 1.31185 \dots \approx 0

Find one solution for

2 y^{2} + 0.57365 \dots y + 1.31185 \dots = 0

using Newton-Raphson:

No Solution for

y \in R

The solution is

y \approx 2.28682 \dots

x^{2} (x + 9) = 0

- x^{3} + 2 x^{2} + 3 x + 2 = 0

x^{3} - 23 x^{2} = 0

515 = 5 x^{3}

(x + 2) (x^{2} - 9) = 0

What are the solutions to the equation 2y^3-4y^2-3=0 ?
The solutions to the equation 2y^3-4y^2-3=0 are y\approx 2.28682…
Find the zeros of 2y^3-4y^2-3=0
The zeros of 2y^3-4y^2-3=0 are y\approx 2.28682…