What are the solutions to the equation (x+2)(x^2-9)=0 ?

The solutions to the equation (x+2)(x^2-9)=0 are x=-2,x=-3,x=3

Find the zeros of (x+2)(x^2-9)=0

The zeros of (x+2)(x^2-9)=0 are x=-2,x=-3,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2) (x^{2} - 9) = 0

x = - 2, x = - 3, x = 3

Solution steps

(x + 2) (x^{2} - 9) = 0

Factor

(x + 2) (x^{2} - 9) : (x + 2) (x + 3) (x - 3)

(x + 2) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 2, x = - 3, x = 3

5 x^{3} + 4 x^{2} - 57 x = 0

2 x^{6} + 7 x^{3} - 15 = 0

x^{3} - 4 x + x (x + 2) = 0

5 x^{4} = 1080 x

x^{3} (x + 1) = - 6

What are the solutions to the equation (x+2)(x^2-9)=0 ?
The solutions to the equation (x+2)(x^2-9)=0 are x=-2,x=-3,x=3
Find the zeros of (x+2)(x^2-9)=0
The zeros of (x+2)(x^2-9)=0 are x=-2,x=-3,x=3