What are the solutions to the equation 5x^3+4x^2-57x=0 ?

The solutions to the equation 5x^3+4x^2-57x=0 are x=0,x=3,x=-19/5

Find the zeros of 5x^3+4x^2-57x=0

The zeros of 5x^3+4x^2-57x=0 are x=0,x=3,x=-19/5

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5 x^{3} + 4 x^{2} - 57 x = 0

x = 0, x = 3, x = - \frac{19}{5}

Decimal Notation

x = 0, x = 3, x = - 3.8

Solution steps

5 x^{3} + 4 x^{2} - 57 x = 0

Factor

5 x^{3} + 4 x^{2} - 57 x : x (x - 3) (5 x + 19)

x (x - 3) (5 x + 19) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0 or 5 x + 19 = 0

Solve

x - 3 = 0 : x = 3

Solve

5 x + 19 = 0 : x = - \frac{19}{5}

The solutions are

x = 0, x = 3, x = - \frac{19}{5}

2 x^{6} + 7 x^{3} - 15 = 0

x^{3} - 4 x + x (x + 2) = 0

5 x^{4} = 1080 x

x^{3} (x + 1) = - 6

x, - y = x^{3}

What are the solutions to the equation 5x^3+4x^2-57x=0 ?
The solutions to the equation 5x^3+4x^2-57x=0 are x=0,x=3,x=-19/5
Find the zeros of 5x^3+4x^2-57x=0
The zeros of 5x^3+4x^2-57x=0 are x=0,x=3,x=-19/5