What are the solutions to the equation x^3-12x^2+47x=60 ?

The solutions to the equation x^3-12x^2+47x=60 are x=3,x=4,x=5

Find the zeros of x^3-12x^2+47x=60

The zeros of x^3-12x^2+47x=60 are x=3,x=4,x=5

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x^{3} - 12 x^{2} + 47 x = 60

x = 3, x = 4, x = 5

Solution steps

x^{3} - 12 x^{2} + 47 x = 60

Move

60

to the left side

x^{3} - 12 x^{2} + 47 x - 60 = 0

Factor

x^{3} - 12 x^{2} + 47 x - 60 : (x - 3) (x - 4) (x - 5)

(x - 3) (x - 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 4 = 0 or x - 5 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 4 = 0 : x = 4

Solve

x - 5 = 0 : x = 5

The solutions are

x = 3, x = 4, x = 5

(1 + x)^{20} = 2

105000 = 27000 \cdot a^{5}

16 x^{3} + 96 x^{2} - 25 x - 150 = 0

c x^{2} + 6 x = x^{3} - c x

x^{4} - 2 x^{3} - 2 x - 1 = 0

What are the solutions to the equation x^3-12x^2+47x=60 ?
The solutions to the equation x^3-12x^2+47x=60 are x=3,x=4,x=5
Find the zeros of x^3-12x^2+47x=60
The zeros of x^3-12x^2+47x=60 are x=3,x=4,x=5