What are the solutions to the equation (x^2-x-22)^4=4096 ?

The solutions to the equation (x^2-x-22)^4=4096 are x=6,x=-5,x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2

Find the zeros of (x^2-x-22)^4=4096

The zeros of (x^2-x-22)^4=4096 are x=6,x=-5,x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2

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(x^{2} - x - 22)^{4} = 4096

x = 6, x = - 5, x = \frac{1 + 57}{2}, x = \frac{1 - 57}{2}

Decimal Notation

x = 6, x = - 5, x = 4.27491 \dots, x = - 3.27491 \dots

Solution steps

(x^{2} - x - 22)^{4} = 4096

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 6, x = - 5, x = \frac{1 + 57}{2}, x = \frac{1 - 57}{2}

x^{3} - 2 x^{2} - 5 x + 3 = 0

r^{3} = 1

x^{3} - 13 x^{2} + 30 x = 0

x^{4} - 16 x^{2} + 32 x - 16 = 0

r^{3} - r^{2} - 4 r + 4 = 0

What are the solutions to the equation (x^2-x-22)^4=4096 ?
The solutions to the equation (x^2-x-22)^4=4096 are x=6,x=-5,x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2
Find the zeros of (x^2-x-22)^4=4096
The zeros of (x^2-x-22)^4=4096 are x=6,x=-5,x=(1+sqrt(57))/2 ,x=(1-sqrt(57))/2