What are the solutions to the equation 3x^3+1=x^2+3x ?

The solutions to the equation 3x^3+1=x^2+3x are x= 1/3 ,x=-1,x=1

Find the zeros of 3x^3+1=x^2+3x

The zeros of 3x^3+1=x^2+3x are x= 1/3 ,x=-1,x=1

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3 x^{3} + 1 = x^{2} + 3 x

x = \frac{1}{3}, x = - 1, x = 1

Decimal Notation

x = 0.33333 \dots, x = - 1, x = 1

Solution steps

3 x^{3} + 1 = x^{2} + 3 x

Move

3 x

to the left side

3 x^{3} + 1 - 3 x = x^{2}

Move

x^{2}

to the left side

3 x^{3} + 1 - 3 x - x^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

3 x^{3} - x^{2} - 3 x + 1 = 0

Factor

3 x^{3} - x^{2} - 3 x + 1 : (3 x - 1) (x + 1) (x - 1)

(3 x - 1) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = \frac{1}{3}, x = - 1, x = 1

x^{3} + 4 x^{2} - 5 x = - 3 x^{2} - 5 x + 15

x^{3} - 10 x^{2} + 24 = 0

2 x^{3} + 3 x - 1 = 0

(x^{2} - 4) (x^{2} + 8 x + 16) = 0

x^{3} - 3 x^{2} - 2 x = 0

What are the solutions to the equation 3x^3+1=x^2+3x ?
The solutions to the equation 3x^3+1=x^2+3x are x= 1/3 ,x=-1,x=1
Find the zeros of 3x^3+1=x^2+3x
The zeros of 3x^3+1=x^2+3x are x= 1/3 ,x=-1,x=1