What are the solutions to the equation -x^3-x^2+6x=0 ?

The solutions to the equation -x^3-x^2+6x=0 are x=0,x=2,x=-3

Find the zeros of -x^3-x^2+6x=0

The zeros of -x^3-x^2+6x=0 are x=0,x=2,x=-3

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- x^{3} - x^{2} + 6 x = 0

x = 0, x = 2, x = - 3

Solution steps

- x^{3} - x^{2} + 6 x = 0

Factor

- x^{3} - x^{2} + 6 x : - x (x - 2) (x + 3)

- x (x - 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x + 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 0, x = 2, x = - 3

2 (x + 1)^{3} - 4 = 12

x^{4} + 4 x^{3} + x + 7 = 9 x + 7

5 x^{5} + x = 10

x^{4} - x^{3} - x^{2} + x = 0

2 x^{3} - 6 x^{2} = 56 x

What are the solutions to the equation -x^3-x^2+6x=0 ?
The solutions to the equation -x^3-x^2+6x=0 are x=0,x=2,x=-3
Find the zeros of -x^3-x^2+6x=0
The zeros of -x^3-x^2+6x=0 are x=0,x=2,x=-3