What are the solutions to the equation x^4+4x^3+x+7=9x+7 ?

The solutions to the equation x^4+4x^3+x+7=9x+7 are x=0,x=-2,x=-1+sqrt(5),x=-1-sqrt(5)

Find the zeros of x^4+4x^3+x+7=9x+7

The zeros of x^4+4x^3+x+7=9x+7 are x=0,x=-2,x=-1+sqrt(5),x=-1-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} + 4 x^{3} + x + 7 = 9 x + 7

x = 0, x = - 2, x = - 1 + 5, x = - 1 - 5

Decimal Notation

x = 0, x = - 2, x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

x^{4} + 4 x^{3} + x + 7 = 9 x + 7

Move

7

to the right side

x^{4} + 4 x^{3} + x = 9 x

Move

9 x

to the left side

x^{4} + 4 x^{3} - 8 x = 0

Factor

x^{4} + 4 x^{3} - 8 x : x (x + 2) (x^{2} + 2 x - 4)

x (x + 2) (x^{2} + 2 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x^{2} + 2 x - 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 2 x - 4 = 0 : x = - 1 + 5, x = - 1 - 5

The solutions are

x = 0, x = - 2, x = - 1 + 5, x = - 1 - 5

5 x^{5} + x = 10

x^{4} - x^{3} - x^{2} + x = 0

2 x^{3} - 6 x^{2} = 56 x

3 y^{3} = 375

2 x (x + 9) (x^{2} - 2) = 0

What are the solutions to the equation x^4+4x^3+x+7=9x+7 ?
The solutions to the equation x^4+4x^3+x+7=9x+7 are x=0,x=-2,x=-1+sqrt(5),x=-1-sqrt(5)
Find the zeros of x^4+4x^3+x+7=9x+7
The zeros of x^4+4x^3+x+7=9x+7 are x=0,x=-2,x=-1+sqrt(5),x=-1-sqrt(5)